vault backup: 2025-10-09 13:25:21
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@@ -115,6 +115,14 @@ either for spec requirements or conduit fill considerations.
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## Voltage Drop
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> [!info] Ohm's Law
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>
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> $$
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> V = I \times R, \quad R = \frac{ V }{ I }, \quad I = \frac{ V }{ R }
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> $$
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### Step 1: Effective Impedance $Z$
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$$
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Z = R \cos(\theta) + X \sin(\theta)
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$$
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@@ -125,47 +133,7 @@ where
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* $X$ = Reactance
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* $\theta$ = Power factor angle = $\arccos(PF)$
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> [!info] 1-Phase, Line to Neutral Voltage Drop
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>
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> $$
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> \Delta V_{LN} = I \times Z \times 2L
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> $$
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> [!info] 1-Phase, Line to Line Voltage Drop
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>
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> $$
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> \Delta V_{LL} = \sqrt{3} \times I \times Z \times 2L
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> $$
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> [!info] 3-Phase Voltage Drop
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>
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> $$
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> \Delta V_{3\phi} = \sqrt{3} \times I \times Z \times L
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> $$
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where
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* $\Delta V$ = Voltage drop in volts ($V$)
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* $I$ = Current in amperes ($A$)
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* $L$ = Length of wire one way in feet ($\text{ft}$)
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It is often more useful to know the maximum length
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a certain wiring configuration is suitable for.
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$$
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L = \frac{ \Delta V }{ I \times M } \times \frac{1}{Z}
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$$
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> [!info] Ohm's Law
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>
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> $$
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> V = I \times R, \quad R = \frac{ V }{ I }, \quad I = \frac{ V }{ R }
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> $$
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> [!important]
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> "Current" is not the OCPD rating,
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> but the actual load.
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## Parallel Runs
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#### Parallel Runs
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The equivalent resistance of parallel resistances is given by
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@@ -183,6 +151,65 @@ $$
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\end{align*}
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$$
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### Step 2: Voltage Drop
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> [!important]
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> This section assumes a 3-phase
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> 208Y/120V or 480Y/277V voltage system
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> [!info] 3-Phase Voltage
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> $$
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> V_{LL} = \sqrt{3} \times V_{LN}, \quad V_{LN} = \frac{V_{LL}}{\sqrt{3}}
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> $$
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3% allowable voltage drop for a 120V line-to-neutral load:
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$$
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\text{Max} \Delta V = 0.03 \times 120 \text{V}_{LN} = 3.6 \text{V}_{LN}
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$$
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3% allowable voltage drop for a 208V line-to-line load:
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$$
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\text{Max} \Delta V = 0.03 \times 208 \text{V}_{LL} = 6.24 \text{V}_{LL}
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$$
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#### Line to Neutral Loads
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$$
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\Delta V_{LN} = I \times Z \times 2L
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$$
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#### Line to Line Loads
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$$
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\Delta V_{LL} = \sqrt{3} \times \left( I \times Z \times 2L \right)
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$$
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#### 3-Phase Loads
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$$
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\Delta V_{3\phi} = \sqrt{3} \times \left( I \times Z \times L \right)
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$$
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where
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* $\Delta V$ = Voltage drop in volts ($V$)
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* $I$ = Current in amperes ($A$)
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* $L$ = Length of wire one way in feet ($\text{ft}$)
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> [!important]
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> "Current" is not the OCPD rating,
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> but the actual load.
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***
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It is often more useful to know the maximum length
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a certain wiring configuration is suitable for.
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$$
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L = \frac{ \Delta V }{ I \times M } \times \frac{1}{Z}
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$$
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## Transformers
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$$
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